I calculated all the required in this problem correctly but can't understand why the sum of energy extracted and absorbed is not zero.
They are:
>0: 0J
0 <=E<=25: 4t^2 J
25 <= E <= 50: 4t^2 - 0.4t + 10 * 10^-3t J
E > 50: 0 J
Does that mean that an inductor stores energy even after there...
Hey everyone,
I am taking a circuit 1 course in college and was wondering if an inductor is actually efficient. What I mean is that does it produce more current than the current already supplied. I know it keeps the circuit going even after the voltage source is cut, but does that mean that, if...
if I am going through the positive terminal of a component, I will write P = +V I
if I am going through the negative terminal of a component, I will write P = - V I
Isn't that correct?
Thank you so much for replying
I did so and got -5 V (with that number how can I determine the positive and negative ends of the current source's voltage?)
I am so sorry if I am posting this in the wrong forum; it is just not a homework problem, and I can't find the right place - it's more of a study help question.
Yes, I understand now what is happening
Thank you so much for clarifying; after the first couple of questions, all involved a triangular arrangement I thought these questions can't be solved without the cosine law!
Thank you so much again for clarifying
does it give that answer if you do so? if Yes, can you tell the difference between this question and that question, please: Three long, straight, parallel wires each carry a current of 10 A in the positive x-direction. If the distance between each wire and the other two is 10 cm, what is the...
This is how I visualize the problem (of course I am drawing this as if it is in the z-y axis); I don't know what will be the next step. Anyone please help me.
Thank you
Thank you
but
if I did this to convert ev to j
sqrt(2 * e * (3000e) / mass) <---- where e is the charge of a proton and 3000e is the ev to joule conversion
I get the wrong answer
When I do this
v = sqrt ( 2 * e * 3000/ mass of the proton) <---- where e is the charge of the proton and 3000 is the ev I get the right answer
So normally I should use (ev) not v
The answer comes out if I convert the ev to joule and work normally using the kinetic energy equation 1/2 m v^2 = E
But what is the mistake when I use the other equation?
v = sqrt( (2 * charge of proton * 3000/e) / (mass of proton))
v = 1.893986024 x 10^`15
r = ( (mass of proton) * (velocity) ) / ((magnetic field) * (charge of proton))
r = 24715769.68 m
Anyone please help
It seems that I've been studying for so long now that I couldn't notice what I first learned in this course
Thank you so much for pointing out my obvious mistake
m = 0.005
q = -70 x 10^-6 c
v = 30,000 m/s
Since there is no movement vertically Fb = Mg
So,
q . V . B = mg
So,
(70 x `10^-6) . (30,000) . B = (0.005) . (9.8)
So,
B = 0.0233333 or ~ 23 MT
8000
0
0
5
-4
3
F = (5 x 10^-6) * up (sorry cant write a materix here)
F = (5 x10^-6) {0i - 24000 j - 32000 k)
F = -0.12 j - 0.16 k
Mag of F = 0.2 (I feel that there is something wrong in the question; I don't know)